document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=162789>Question 162789</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can I please get help with:\r<BR>\n" );
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document.write( "(12)/(3x-2)+(5)/(x+4)=1<BR>\n" );
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document.write( "Thanks you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119986 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119986\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (12)/(3x-2)+(5)/(x+4)=1<BR>\n" );
document.write( "12(x+4)+5(3x-2)=(3x-2)(x+4) multiply each side by the LCM to eliminate fractions.<BR>\n" );
document.write( "12x+48+15x-10=3x^2+10x-8<BR>\n" );
document.write( "27x+38=3x^2+10x-8<BR>\n" );
document.write( "3x^2-17x-46=0 Subtract the left side from the right.<BR>\n" );
document.write( "3*-46=-138<BR>\n" );
document.write( "factors of -138 that add up to -17: 6 & -23<BR>\n" );
document.write( "3x^2+6x-23x-46=0<BR>\n" );
document.write( "3x(x+2)-23(x+2)=0 Factoring by grouping. (easier)<BR>\n" );
document.write( "(3x-23)(x+2)=0<BR>\n" );
document.write( "x=-2, x=23/3<BR>\n" );
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document.write( "Ed<BR>\n" );
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