document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=162776>Question 162776</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is twice the width. The area is 18yd^2. Find the length and width.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119979 by </B><A HREF=/tutors/aboutme.mpl?userid=Anthea+Lawn><B>Anthea Lawn(22)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Anthea+Lawn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119979\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the width of the rectangle = w\r<BR>\n" );
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document.write( "The length is twice this, which is 2w.\r<BR>\n" );
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document.write( "The area is the length times the width = (w)(2w) = 18\r<BR>\n" );
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document.write( "2w^2 - 18<BR>\n" );
document.write( "w^2 = 9\r<BR>\n" );
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document.write( "Therefore width = 3 yards, length = 6 yards. </SPAN>\n" );
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