document.write( "Question 162733: The funtions are f(x)=2x^2+5x+7 and g(x)=x^3 + 2
\n" ); document.write( "The directions say evaluate the following: and identify the domain of each
\n" ); document.write( "The question is (f/g)(x)
\n" ); document.write( "I got 2x^2+5x+7/x^3+2 would the domain be that x cant equal 2?
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Algebra.Com's Answer #119949 by gonzo(654)\"\" \"About 
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The funtions are f(x)=2x^2+5x+7 and g(x)=x^3 + 2
\n" ); document.write( "The directions say evaluate the following: and identify the domain of each
\n" ); document.write( "The question is (f/g)(x)
\n" ); document.write( "I got 2x^2+5x+7/x^3+2 would the domain be that x cant equal 2?
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\n" ); document.write( "f/g(x) = f(x)/g(x) so that part is correct.
\n" ); document.write( "the domain of f(x) and the domain of g(x) is the set of all real numbers.
\n" ); document.write( "the domain of f(x)/g(x) should be all all real numbers with the exception that the denominator can't be 0.
\n" ); document.write( "the denominator is 0 when g(x) is 0.
\n" ); document.write( "g(x) is 0 when x^3 is -2.
\n" ); document.write( "x^3 is -2 when x = cube root of -2.
\n" ); document.write( "the domain of f/g(x) is all values of x except cube root of -2.
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\n" ); document.write( "that's what i think.
\n" ); document.write( "looks like you had the right idea.
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