document.write( "Question 162733: The funtions are f(x)=2x^2+5x+7 and g(x)=x^3 + 2
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document.write( "The directions say evaluate the following: and identify the domain of each
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document.write( "The question is (f/g)(x)
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document.write( "I got 2x^2+5x+7/x^3+2 would the domain be that x cant equal 2? \n" );
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Algebra.Com's Answer #119949 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! The funtions are f(x)=2x^2+5x+7 and g(x)=x^3 + 2 \n" ); document.write( "The directions say evaluate the following: and identify the domain of each \n" ); document.write( "The question is (f/g)(x) \n" ); document.write( "I got 2x^2+5x+7/x^3+2 would the domain be that x cant equal 2? \n" ); document.write( "------------------------------------------------------------------------------ \n" ); document.write( "f/g(x) = f(x)/g(x) so that part is correct. \n" ); document.write( "the domain of f(x) and the domain of g(x) is the set of all real numbers. \n" ); document.write( "the domain of f(x)/g(x) should be all all real numbers with the exception that the denominator can't be 0. \n" ); document.write( "the denominator is 0 when g(x) is 0. \n" ); document.write( "g(x) is 0 when x^3 is -2. \n" ); document.write( "x^3 is -2 when x = cube root of -2. \n" ); document.write( "the domain of f/g(x) is all values of x except cube root of -2. \n" ); document.write( "----- \n" ); document.write( "that's what i think. \n" ); document.write( "looks like you had the right idea. \n" ); document.write( " \n" ); document.write( " |