document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=162570>Question 162570</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0176157042/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> im having trouble with two questios, i just dont understand them. i know i have to use the formula for distance or radius (r = xsqaured + y sqaured) but i dont know how to apply it. the questions are \r<BR>\n" );
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document.write( "A rock dropped into a pond sends out a circular ripple whose radius increases steadily at 6cm/s. A toy boat is floating on the pond 2 m east and 1 m north of the spot where the rock is dropped. How long does it take for the rippe to reach the boat \r<BR>\n" );
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document.write( "the second question is \r<BR>\n" );
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document.write( "A triangle has vertices at s (6,6), t(-6,12), and u(0,-12). SM is the median from the vertex S. Find the coordinates of the point that is two-thirds of the way frm S to M. \r<BR>\n" );
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document.write( "I dont know how to apply toe distance formuls, radius or mid point formula. I really need your help, i have a test tomorrow.\r<BR>\n" );
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document.write( "Thank you <BR>\n" );
document.write( "- Neha =)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119908 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119908\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 meters east, 1 meter north.<BR>\n" );
document.write( "The distance (radius) from the center of rock drop to toy boat is,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=D=sqrt%28x%5E2%2By%5E2%29 ALIGN=MIDDLE  ALT=\"D=sqrt%28x%5E2%2By%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=D=sqrt%282%5E2%2B1%5E2%29=sqrt%284%2B1%29=sqrt%285%29 ALIGN=MIDDLE  ALT=\"D=sqrt%282%5E2%2B1%5E2%29=sqrt%284%2B1%29=sqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=D=2.23606 ALIGN=MIDDLE  ALT=\"D=2.23606\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "So the center of the rock drop is 2.23606 meters away from the toy boat. <BR>\n" );
document.write( "The ripple is moving towards the boat at 6 cm/s. <BR>\n" );
document.write( "This is now a rate x time=distance problem.<BR>\n" );
document.write( "You know the rate, the speed of the ripple.<BR>\n" );
document.write( "You calculated the distance.<BR>\n" );
document.write( "Now calculate the time.<BR>\n" );
document.write( "First, the units have to match (can't mix cm and m).<BR>\n" );
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document.write( "Change the distance to cm.<BR>\n" );
document.write( "2.23606 meters= 223.6cm<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R%2AT=D ALIGN=MIDDLE  ALT=\"R%2AT=D\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=T=D%2FR ALIGN=MIDDLE  ALT=\"T=D%2FR\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=T=223.6%2F6=37.27 ALIGN=MIDDLE  ALT=\"T=223.6%2F6=37.27\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "It will take the ripple 37.27 seconds to reach the boat.<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28+300%2C+300%2C+-12%2C+12%2C+-15%2C+15%2Cgrid%28+1+%29%2Ccircle%28+0%2C+-12%2C+.2+%29%2C%0D%0Alocate%286%2C6%2CS%29%2C%0D%0Alocate%28-7%2C12%2CT%29%2C%0D%0Alocate%281%2C-10%2CU%29%2C%0D%0Acircle%28+6%2C+6%2C+.2+%29%2C%0D%0Acircle%28+-6%2C+12%2C+.2+%29%2C%0D%0Agreen%28line%280%2C-12%2C6%2C6%29%29%2C%0D%0Agreen%28line%286%2C6%2C-6%2C12%29%29%2C%0D%0Agreen%28line%28+-6%2C+12%2C+0%2C+-12%29%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "M is the midpoint of the line from T to U.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5BM%5D=%28-6%2B0%29%2F2=-3 ALIGN=MIDDLE  ALT=\"x%5BM%5D=%28-6%2B0%29%2F2=-3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5BM%5D=%2812%2B%28-12%29%29%2F2=0 ALIGN=MIDDLE  ALT=\"y%5BM%5D=%2812%2B%28-12%29%29%2F2=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The midpoint M has coordinates (-3,0).<BR>\n" );
document.write( "The change in x from S to M is <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=DELTA%2Ax=%28-3-6%29=-9 ALIGN=MIDDLE  ALT=\"DELTA%2Ax=%28-3-6%29=-9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The change in y from S to M is<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=DELTA%2Ay=%280-6%29=-6 ALIGN=MIDDLE  ALT=\"DELTA%2Ay=%280-6%29=-6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Using only 2/3 of the change in x, you would have,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%2F3%29%28-9%29=-6 ALIGN=MIDDLE  ALT=\"%282%2F3%29%28-9%29=-6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Using only 2/3 of the change in y, you would have,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%2F3%29%28-6%29=-4 ALIGN=MIDDLE  ALT=\"%282%2F3%29%28-6%29=-4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "My starting point is S at (6,6).<BR>\n" );
document.write( "The point P is 2/3 of the way from S to M.<BR>\n" );
document.write( "The coordinates of P are found by starting at S and adding the 2/3 change in x and y.<BR>\n" );
document.write( "(6,6)+(-6,-4)=(0,2)<BR>\n" );
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document.write( "P is located at (0,2)<BR>\n" );
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document.write( ".<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28+300%2C+300%2C+-12%2C+12%2C+-15%2C+15%2Cgrid%28+1+%29%2Ccircle%28+0%2C+-12%2C+.2+%29%2C%0D%0Alocate%286%2C6%2CS%29%2C%0D%0Alocate%281%2C2.5%2CP%29%2C%0D%0Alocate%28-7%2C12%2CT%29%2C%0D%0Alocate%28-3%2C2%2CM%29%2C%0D%0Alocate%281%2C-10%2CU%29%2C%0D%0Acircle%28+6%2C+6%2C+.2+%29%2C%0D%0Acircle%28+-6%2C+12%2C+.2+%29%2C%0D%0Acircle%28-3%2C0%2C.4%29%2C%0D%0Acircle%280%2C2%2C.4%29%2C%0D%0Acircle%28-3%2C0%2C.2%29%2C%0D%0Acircle%280%2C2%2C.2%29%2C%0D%0Ablue%28line%286%2C6%2C-3%2C0%29%29%2C%0D%0Agreen%28line%280%2C-12%2C6%2C6%29%29%2C%0D%0Agreen%28line%286%2C6%2C-6%2C12%29%29%2C%0D%0Agreen%28line%28+-6%2C+12%2C+0%2C+-12%29%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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