document.write( "Question 162680: A homeowner wants to fence a rectangular garden using 120ft of fencing. The side of the garage will be used as one side of the rectangle. Find the dimension for which the area is a maximum.
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Algebra.Com's Answer #119899 by nerdybill(7384)\"\" \"About 
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Let w = width
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\n" ); document.write( "then:
\n" ); document.write( "2w + L = 120 (equation 1)
\n" ); document.write( "and
\n" ); document.write( "area = wL (equation 2)
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\n" ); document.write( "Solve for L in equation 1:
\n" ); document.write( "2w + L = 120
\n" ); document.write( "L = 120-2w
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\n" ); document.write( "Substitute the above into equation 2:
\n" ); document.write( "area = wL
\n" ); document.write( "area = w(120-2w)
\n" ); document.write( "area = 120w-2w^2
\n" ); document.write( "area = -2w^2+120w
\n" ); document.write( "area = -2(w^2-60w)
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\n" ); document.write( "The standard parabola equation is:
\n" ); document.write( "y= a(x-h)2+k
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\n" ); document.write( "Strategy is manipulate the equation so that it fits that form (to find the vertex) -- do this by completing the square:
\n" ); document.write( "area = -2(w^2-60w)
\n" ); document.write( "area = -2(w^2-60w+900)+1800
\n" ); document.write( "area = -2(w-30)^2+1800
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\n" ); document.write( "(h,k) is the vertex:
\n" ); document.write( "(30,1800)
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\n" ); document.write( "Therefore, area is maximized when
\n" ); document.write( "w = 30 feet (width)
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\n" ); document.write( "to find the length, we said the length is:
\n" ); document.write( "L = 120-2w
\n" ); document.write( "L = 120-2(30)
\n" ); document.write( "L = 120-60
\n" ); document.write( "L = 60 feet (length)
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\n" ); document.write( "Conclusion:
\n" ); document.write( "dimension is 30 by 60 feet rectangle
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