document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=162681>Question 162681</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the measure of an angle if its suppliment measures 12degrees less than three times its compliment<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119898 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119898\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "supplement is when two angles summed together is 180 deg.<BR>\n" );
document.write( "complement is when two angles summed together is 90 deg.<BR>\n" );
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document.write( "Let x = \"the angle\"<BR>\n" );
document.write( "then<BR>\n" );
document.write( "90-x = the complement<BR>\n" );
document.write( "180-x = the supplement<BR>\n" );
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document.write( "180-x = 3(90-x)-12<BR>\n" );
document.write( "180-x = 270-3x-12<BR>\n" );
document.write( "180-x = 258-3x<BR>\n" );
document.write( "180+2x = 258<BR>\n" );
document.write( "2x = 78<BR>\n" );
document.write( "x = 39 degrees (measure of the angle)\r<BR>\n" );
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