document.write( "Question 162661: WITH THE CURRENT, A SAILBOAT TRAVELS 9 KM IN 3 HRS. HOWEVER IF IT TRAVELS AGAINST THE CURRENT, IT TAKES 3 TIMES TO SAIL THE SAME DISTANCE, HOW FAST IS THE BOAT SAILING ON STILL WATER? HOW FAST DOES THE RIVER FLOW? \n" ); document.write( "
Algebra.Com's Answer #119896 by josmiceli(19441)\"\" \"About 
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\"s\"= speed in still water
\n" ); document.write( "\"c\"= speed of current
\n" ); document.write( "\"9+=+%28s+%2B+c%29%2A3\"
\n" ); document.write( "\"9+=+%28s+-+c%29%2A9\"
\n" ); document.write( "-------------------
\n" ); document.write( "(1) \"9+=+3s+%2B+3c\"
\n" ); document.write( "(2) \"9+=+9s+-+9c\"
\n" ); document.write( "Divide both sides of (2) by \"3\" and add it to (1)
\n" ); document.write( "(1) \"9+=+3s+%2B+3c\"
\n" ); document.write( "(2) \"3+=+3s+-+3c\"
\n" ); document.write( "\"12+=+6s\"
\n" ); document.write( "\"s+=+2\" km/hr
\n" ); document.write( "(1) \"3+=+3%2A2+-+3c\"
\n" ); document.write( "\"-3+=+-3c\"
\n" ); document.write( "\"c+=+1\"km/hr
\n" ); document.write( "The speed of the boat in still water is 2 km/hr
\n" ); document.write( "The speed of the current is 1 km/hr
\n" ); document.write( "
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