document.write( "Question 162663: A MAN ROWED 10 KM UP A RIVER IN 5 HOURS AND BACK IN 21 AND A HALF HOURS. FIND THE RATE OF THE CURRENT AND HIS RATE OF ROWING IN STILL WATER. \n" ); document.write( "
Algebra.Com's Answer #119879 by josmiceli(19441)\"\" \"About 
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Let his rate in still water = \"s\"
\n" ); document.write( "Let the rate of the current = \"c\"
\n" ); document.write( "His rate against the current is \"s+-+c\"
\n" ); document.write( "His rate with the current is \"s+%2B+c\"
\n" ); document.write( "The distance both ways is \"10\"km
\n" ); document.write( "distance = rate * time
\n" ); document.write( "(1) \"10+=+%28s+%2B+c%29%2A5\" mi (with the current)
\n" ); document.write( "(2) \"10+=+%28s+-+c%29%2A21.5\" mi (against the current)
\n" ); document.write( "----------------------------------------------------
\n" ); document.write( "(1) \"10+=+5s+%2B+5c\"
\n" ); document.write( "(2) \"10+=+21.5s+-+21.5c\"
\n" ); document.write( "Multiply both sides of (2) by \"10\"
\n" ); document.write( "(2) \"100+=+215s+-+215c\"
\n" ); document.write( "Multiply both sides of (1) by \"43\"
\n" ); document.write( "(1) \"430+=+215s+%2B+215c\"
\n" ); document.write( "(2) \"100+=+215s+-+215c\" Now add the equations
\n" ); document.write( "(3) \"530+=+430s\"
\n" ); document.write( "\"s+=+1.233\"km/hr
\n" ); document.write( "(1) \"10+=+5s+%2B+5c\"
\n" ); document.write( "\"5c+=+10+-+5%2A1.233\"
\n" ); document.write( "\"5c+=+10+-+6.163\"
\n" ); document.write( "\"5c+=+3.837\"
\n" ); document.write( "\"c+=+.7674\"km/hr
\n" ); document.write( "His rate in still water is 1.233 km/hr
\n" ); document.write( "The rate of the current is .7674 km/hr
\n" ); document.write( "check answer:
\n" ); document.write( "(1) \"10+=+%28s+%2B+c%29%2A5\"
\n" ); document.write( "(2) \"10+=+%28s+-+c%29%2A21.5\"
\n" ); document.write( "--------------------------
\n" ); document.write( "(1) \"10+=+%281.233+%2B+.7674%29%2A5\"
\n" ); document.write( "\"10+=+2.0004%2A5\"
\n" ); document.write( "\"10+=+10.002\" error due to rounding off
\n" ); document.write( "(2) \"10+=+%28s+-+c%29%2A21.5\"
\n" ); document.write( "\"10+=+%281.233+-+.7674%29%2A21.5\"
\n" ); document.write( "\"10+=+.4656%2A21.5\"
\n" ); document.write( "\"10+=+10.010\" (error due to rounding)
\n" ); document.write( "OK
\n" ); document.write( "
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