document.write( "Question 162580: the measure of an amgle is 35 more than twice the complement of the angle. Find the measure of the angle, its supplement, and its complement\r \n" );
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document.write( "Note: The complement of an angle is always 90-(angle); the supplement of an angle is always 180-(angle)\r \n" );
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document.write( "Let x= angle1 \n" );
document.write( "Then 90-x=complement of angle1 \n" );
document.write( "180-x=supplement of angle1\r \n" );
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document.write( "Now lets translate from words to algebra: \n" );
document.write( "x =2(90-x)+35 \n" );
document.write( "x=180-2x+35 \n" );
document.write( "x=215-2x \n" );
document.write( "x+2x=215-2x+2x \n" );
document.write( "3x=215+0 \n" );
document.write( "3x/3=215/3 \n" );
document.write( "x=215/3 \n" );
document.write( "complement = 90-(215/3)=(270/3)-(215/3)=55/3 \n" );
document.write( "supplement = 180-(215/3)=(540/3)-(215/3)=325/3\r \n" );
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document.write( "According to person who posted problem, it should be set up as follows: \n" );
document.write( "180-x = 2(90-x)+ 35 \n" );
document.write( "yet 180-x stands for the measure of the supplement of an angle...setting up the problem like this would be correct if the problem was the following: \n" );
document.write( "THE MEASURE OF THE SUPPLEMENT OF AN ANGLE IS 35 MORE THAN TWICE THE COMPLEMENT OF THE ANGLE. FIND THE MEASURE OF THE ANGLE, ITS SUPPLEMENT, AND ITS COMPLEMENT\r \n" );
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