document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=162521>Question 162521</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find four consecutive integers such that twice the sum of the two greater integers exceeds three times the first by 91. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119781 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119781\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     Find four consecutive integers such that twice the sum of the two greater integers exceeds three times the first by 91.<BR>\n" );
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document.write( "Let x = first (smallest) consecutive integer<BR>\n" );
document.write( "x+1 = second consecutive integer<BR>\n" );
document.write( "x+2 = third consecutive integer<BR>\n" );
document.write( "x+3 = fourth (largest) consecutive integer<BR>\n" );
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document.write( "2[(x+2)+(x+3)] = 3x+91<BR>\n" );
document.write( "2[2x+5] = 3x+91<BR>\n" );
document.write( "4x+10 = 3x+91<BR>\n" );
document.write( "x+10 = 91<BR>\n" );
document.write( "x = 81<BR>\n" );
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document.write( "Therefore, the integers are:<BR>\n" );
document.write( "81, 82, 83, and 84<BR>\n" );
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