document.write( "Question 162534This question is from textbook Biginning Algebra
\n" ); document.write( ": The length of a standard jewel case is 2cm more than it's width . The are of the rectangular top of the case is 168 cm squared . Find the length and width of the jewel case. \n" ); document.write( "
Algebra.Com's Answer #119779 by checkley77(12844)\"\" \"About 
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L=W+2
\n" ); document.write( "AREA=L*W
\n" ); document.write( "168=(W+2)W
\n" ); document.write( "168=W^2+2W
\n" ); document.write( "W^2+2W-168=0
\n" ); document.write( "(W-12)(X+14)=0
\n" ); document.write( "W-12=0
\n" ); document.write( "W=12 IS THE WIDTH.
\n" ); document.write( "L=12+2=14 IS THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "168=12*14
\n" ); document.write( "168=168
\n" ); document.write( "
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