document.write( "Question 162511: please show me how to graph the following equation!
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document.write( "1) y=2x-3
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document.write( "2) 6x+8=4x-2y
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document.write( "3) y=|x|+2
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document.write( "4) 3x+4=x-6\r
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document.write( "These are examples of what I am having trouble with. If you can help me out I would apprieate it. \n" );
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Algebra.Com's Answer #119754 by vleith(2983)![]() ![]() ![]() You can put this solution on YOUR website! 1 2 and 4 are all lines. Collect like terms first \n" ); document.write( "1) is already ok as is y = 2x -3 \n" ); document.write( "2) becomes 2x+2y -8 = 0 \n" ); document.write( "4 becomes 2x = -10, which become x = -5\r \n" ); document.write( "\n" ); document.write( "For each of these, set x=0 and solve for y. This gives you one point on the line. \n" ); document.write( "Then set y=0 and solve for x. That gives you a second point. Then just draw a line through those 2 points.\r \n" ); document.write( "\n" ); document.write( "So for 1) when x=0, y=2*0 -3 --> y=-3. So one point is (0, -3) \n" ); document.write( "when y = 0, 0=2x-3 --> x = 3/2. So another point is (-3/2, 0). \n" ); document.write( "Then plot those points and draw the line \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Do the same thing for number 2.\r \n" ); document.write( "\n" ); document.write( "Num ber 4 is a littel diffrerent.There is no y to solve. So every point with an x=-5 is on the line. For instance (-5,0) and (-5,1) Plot them and draw the line. It is a vertical line.\r \n" ); document.write( "\n" ); document.write( "Problem 3 is a little different because is has an absolute value in it. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "That can be written as two equations. \n" ); document.write( " \n" ); document.write( "Solve both of these and plot them both \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |