document.write( "Question 162431: A and B working together can do a job in 20/3 hours. A became ill after 3 hours of working with B and B finished the job, continuing the work alone in 33/4 more hours. How long would it take each working alone to do the job???? \n" ); document.write( "
Algebra.Com's Answer #119750 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A and B working together can do a job in 20/3 hours. A becames ill after 3 hours
\n" ); document.write( " of working with B and B finished the job, continuing the work alone in 33/4 more
\n" ); document.write( " hours. How long would it take each working alone to do the job????
\n" ); document.write( ":
\n" ); document.write( "Let a = A's time working alone
\n" ); document.write( "Let b = B's time working alone
\n" ); document.write( "Let the completed job = 1
\n" ); document.write( ":
\n" ); document.write( "Equation 1, for the statement,\"A and B working together can do a job in 20/3 hours\"
\n" ); document.write( "\"%2820%2F3%29%2Fa\" + \"%2820%2F3%29%2Fb\" = 1
\n" ); document.write( "Which is:
\n" ); document.write( "\"20%2F%283a%29\" + \"20%2F%283b%29\" = 1; (we invert the dividing fraction and multiply)
\n" ); document.write( ":
\n" ); document.write( "Equation 2 when A gets sick:
\n" ); document.write( "B works 3 hr + 33/4 hr = 45/4; hrs total for B
\n" ); document.write( ":
\n" ); document.write( "\"3%2Fa\" + \"45%2F%284b%29\" = 1
\n" ); document.write( "Multiply the 1st fraction by 3/3 to have same denominator as the 1st equation
\n" ); document.write( "\"9%2F%283a%29\" + \"45%2F%284b%29\" = 1
\n" ); document.write( ";
\n" ); document.write( "Try to use elimination here with these two equations:
\n" ); document.write( "\"9%2F%283a%29\" + \"45%2F%284b%29\" = 1
\n" ); document.write( "\"20%2F%283a%29\" + \"20%2F%283b%29\" = 1
\n" ); document.write( ":
\n" ); document.write( "Multiply the 1st equation by 20, and the 2nd equation by 9, results:
\n" ); document.write( "\"180%2F%283a%29\" + \"900%2F%284b%29\" = 20
\n" ); document.write( "\"180%2F%283a%29\" + \"180%2F%283b%29\" = 9
\n" ); document.write( "---------------------------------------subtraction eliminates a, leaving:
\n" ); document.write( "\"900%2F%284b%29\" - \"180%2F%283%29\" = 11
\n" ); document.write( "\"225%2Fb\" - \"60%2Fb\" = 11; reduced the fractions
\n" ); document.write( "\"165%2Fb\" = 11
\n" ); document.write( "b = \"165%2F11\"
\n" ); document.write( "b = 15 hrs by himself
\n" ); document.write( ":
\n" ); document.write( "Find a using eq: \"20%2F%283a%29\" + \"20%2F%283b%29\" = 1;
\n" ); document.write( "\"20%2F%283a%29\" + \"20%2F%283%2A15%29\" = 1;
\n" ); document.write( "\"20%2F%283a%29\" + \"20%2F45\" = 1;
\n" ); document.write( "\"20%2F%283a%29\" + \"4%2F9\" = 1; reduced the fraction
\n" ); document.write( "\"20%2F%283a%29\" = 1 - \"4%2F9%29\"
\n" ); document.write( "\"20%2F%283a%29\" = \"5%2F9%29\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "5(3a) = 20*9
\n" ); document.write( "15a = 180
\n" ); document.write( "a = \"180%2F15\"
\n" ); document.write( "a = 12 hrs by himself
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution using eq;\"9%2F%283a%29\" + \"45%2F%284b%29\" = 1
\n" ); document.write( "\"9%2F%2836%29\" + \"45%2F%2860%29\" = 1
\n" ); document.write( "\"1%2F4\" + \"3%2F4%29\" = 1; confirms the solutions to this horrible problem!\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );