document.write( "Question 162435: an amount of money is invested @ 4% annual simple interest, and twice the amount is invested at 5%. The total annual interest is $112. How much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #119742 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .05*2x+.04x=112 \n" ); document.write( ".10x+.04x=112 \n" ); document.write( ".14x=112 \n" ); document.write( "x=112/.14 \n" ); document.write( "x=800 is the amount invested @ 4% \n" ); document.write( "2*800=1600 invested @ 5%. \n" ); document.write( "Proof: \n" ); document.write( ".05*1600+.04*800=112 \n" ); document.write( "80+32=112 \n" ); document.write( "112=112 \n" ); document.write( " |