document.write( "Question 162435: an amount of money is invested @ 4% annual simple interest, and twice the amount is invested at 5%. The total annual interest is $112. How much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #119742 by checkley77(12844)\"\" \"About 
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.05*2x+.04x=112
\n" ); document.write( ".10x+.04x=112
\n" ); document.write( ".14x=112
\n" ); document.write( "x=112/.14
\n" ); document.write( "x=800 is the amount invested @ 4%
\n" ); document.write( "2*800=1600 invested @ 5%.
\n" ); document.write( "Proof:
\n" ); document.write( ".05*1600+.04*800=112
\n" ); document.write( "80+32=112
\n" ); document.write( "112=112
\n" ); document.write( "
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