document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=162455>Question 162455</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A Rectangular field whose length is 10 meters longer than its width is to be enclosed with exactly 100 meters of fencing material. What are the dimensions of the field? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119717 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119717\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let L = the length of the field and W = the width of the field.<BR>\n" );
document.write( "From the problem description, you have:<BR>\n" );
document.write( "L = W+10 \"...length is 10 meters longer than its width...\"<BR>\n" );
document.write( "The perimeter of a rectangle is given by:<BR>\n" );
document.write( "P = 2(L+W) and this is 100 meters, substituting L = W+10 and P = 100, you get:<BR>\n" );
document.write( "100 = 2((W+10)+W) Simplifying this, you get:<BR>\n" );
document.write( "100 = 2(2W+10) Divide both sides by 2.<BR>\n" );
document.write( "50 = (2W+10) Subtracting 10 from both sides gives you:<BR>\n" );
document.write( "40 = 2W Finally, dividing both sides by 2, you'll get:<BR>\n" );
document.write( "W = 20 and L = W+10 = 20+10 = 30.<BR>\n" );
document.write( "The length of the field is 30 meters and the width of the field is 20 meters. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );