document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=162432>Question 162432</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the area of a rectangle is 675sq.cm. If the width is 1/3 of the length. Find the dimensions of the rectangle???? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119707 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119707\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the area of a rectangle is 675sq.cm. If the width is 1/3 of the length. Find the dimensions of the rectangle????<BR>\n" );
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document.write( "Let x = length of rectangle<BR>\n" );
document.write( "then from \"the width is 1/3 of the length\"<BR>\n" );
document.write( "x/3 = width of rectangle<BR>\n" );
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document.write( "area = length*width<BR>\n" );
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document.write( "675 = x(x/3)<BR>\n" );
document.write( "2025 = x^2<BR>\n" );
document.write( "taking the square root of both sides:<BR>\n" );
document.write( "45 cm = x (length)<BR>\n" );
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document.write( "width:<BR>\n" );
document.write( "x/3 = 45/3 = 15 cm (width) </SPAN>\n" );
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