document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=162409>Question 162409</A>: <I><SPAN STYLE=\"word-break: break-all;\"> angles 1 and 2 are supplementary . Angle 2 is 30 degrees more than twice the measure of Angle 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119689 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119689\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     angles 1 and 2 are supplementary . Angle 2 is 30 degrees more than twice the measure of Angle 1<BR>\n" );
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document.write( "If two angles are supplementary, then the sum of the two angles is 180 deg.<BR>\n" );
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document.write( "Let x = measure of angle 1<BR>\n" );
document.write( "then<BR>\n" );
document.write( "2x+30 = measure of angle 2<BR>\n" );
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document.write( "x + 2x+30 = 180<BR>\n" );
document.write( "3x+30 = 180<BR>\n" );
document.write( "3x = 150<BR>\n" );
document.write( "x = 50 degrees (angle 1)<BR>\n" );
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document.write( "angle 2:<BR>\n" );
document.write( "2x+30 = 2(50)+30 = 100+30 = 130 deg (angle 2) </SPAN>\n" );
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