document.write( "Question 162354: sqrt(x+2) + sqrt(3x+4) = 2 \n" ); document.write( "
Algebra.Com's Answer #119687 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "multiply both sides by \n" ); document.write( " \n" ); document.write( "since \n" ); document.write( "this equation becomes \n" ); document.write( " \n" ); document.write( "which is the same as \n" ); document.write( " \n" ); document.write( "multiplying out on the right hand side of the equation and it becomes \n" ); document.write( " \n" ); document.write( "this becomes \n" ); document.write( " \n" ); document.write( "which becomes \n" ); document.write( " \n" ); document.write( "subtracting 8 and 3*x from both sides of the equation and it becomes \n" ); document.write( " \n" ); document.write( "multiplying both sides of the eqution by (-1) and it becomes \n" ); document.write( " \n" ); document.write( "squaring both sides of the equation and it becomes \n" ); document.write( " \n" ); document.write( "which becomes \n" ); document.write( " \n" ); document.write( "subtracting 48*x and 64 from both sides of the equation and it becomes \n" ); document.write( " \n" ); document.write( "dividing both sides of the equation by 4 and it becomes \n" ); document.write( " \n" ); document.write( "this factors out into \n" ); document.write( " \n" ); document.write( "x is either 7 or -1. \n" ); document.write( "----- \n" ); document.write( "substituting in original equation, x = 7 doesn't work, but x = -1 does. \n" ); document.write( "answer is x = -1.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |