document.write( "Question 162372: solve for the indicated variable
\n" ); document.write( " S=B+1/2Pc
\n" ); document.write( " solve for c \r
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\n" ); document.write( "\n" ); document.write( "please and thanks
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Algebra.Com's Answer #119663 by Alan3354(69443)\"\" \"About 
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S=B+1/2Pc
\n" ); document.write( "solve for c
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\n" ); document.write( "To \"solve for\" c means to get c on one side of the equal sign by itself.
\n" ); document.write( "S=B+1/2Pc
\n" ); document.write( "Subtract B from both sides
\n" ); document.write( "S-B = 1/2Pc
\n" ); document.write( "Multiply both sides by 2
\n" ); document.write( "2S-2B = Pc
\n" ); document.write( "Pc = 2S-2B
\n" ); document.write( "Divide by P
\n" ); document.write( "c = (2S-2B)/P\r
\n" ); document.write( "\n" ); document.write( "It's just a matter of moving things around. Carefully.
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