document.write( "Question 162351: Mr. Turner has a motorboat that can travel 14 mph in still water. He wishes to take a trip on a river whose current flows at the rate of 2 mph. If he has 7 hours at his disposal, how many hours should he spend on the first part of his trip going downstream before returning upstream to his starting point? \n" ); document.write( "
Algebra.Com's Answer #119662 by ankor@dixie-net.com(22740)\"\" \"About 
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Mr. Turner has a motorboat that can travel 14 mph in still water.
\n" ); document.write( " He wishes to take a trip on a river whose current flows at the rate of 2 mph.
\n" ); document.write( " If he has 7 hours at his disposal, how many hours should he spend on the first
\n" ); document.write( " part of his trip going downstream before returning upstream to his starting point?
\n" ); document.write( ":
\n" ); document.write( "Let t = time going down-stream
\n" ); document.write( "then
\n" ); document.write( "(7-t) = time going up-stream
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\n" ); document.write( "14 + 2 = 16 mph; boat speed down-stream
\n" ); document.write( "14 - 2 - 12 mph; boat speed up-stream
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\n" ); document.write( "Distance both ways are the same, write a dist equation: dist = speed * time
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\n" ); document.write( "Dist down = dist up
\n" ); document.write( "16t = 12(7-t)
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\n" ); document.write( "16t = 84 - 12t
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\n" ); document.write( "16t + 12t = 84
\n" ); document.write( ":
\n" ); document.write( "28t = 84
\n" ); document.write( "t = \"84%2F28\"
\n" ); document.write( "t = 3 hrs he can travel down-stream, before he has 4 hrs to return
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\n" ); document.write( "confirm solution by finding the distances down and back:
\n" ); document.write( "16*3 = 48 mi
\n" ); document.write( "12*4 = 48 mi
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