document.write( "Question 162357: PIPE A CAN FILL A POOL IN 12 HOURS. AFTER IT HAS BEEN USED FOR 4.5 HOURS.
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document.write( "PIPE B IS ALSO USED; AND THE POOL IS FILLED IS ANOTHER 4.5 HOURS. HOW LONG WOULD IT TAKE FOR PIPE B TO FILL THE POOL BY ITSELF.\r
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document.write( "PIPE A RATE 1/12
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document.write( "PIPE B RATE = Z
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document.write( "PIPE A RUNS FOR T WHICH IS 4.5 + 4.5 = 9
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document.write( "PIPE B RUNS T - 4.5\r
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document.write( "T*R = w
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document.write( "T(1/12) + T-4.5(1/Z)=1
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document.write( "9(1/12) + 9-4.5(1/Z)=1
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document.write( "9/12 + 4.5/Z =1
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document.write( "4.5/Z = 1-9/12
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document.write( "4.5/Z = 3/12
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document.write( "4.5/Z = 1/4
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document.write( "Z = 18 HRS\r
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document.write( "WHERE DID GO WRONG?\r
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document.write( "
Algebra.Com's Answer #119654 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! you managed to \"stumble\" onto the correct answer\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you defined Z as the rate __ \"PIPE B RATE = Z\" \n" ); document.write( "__ but then used 1/Z in your calculations\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"T*R = w\" \n" ); document.write( "\"T(1/12) + T-4.5(1/Z)=1\" \n" ); document.write( "\"9(1/12) + 9-4.5(1/Z)=1\" \n" ); document.write( " |