document.write( "Question 162337This question is from textbook Elementary and Intermediate
\n" ); document.write( ": Factor each polynomial, if the polynomial is prime say so\r
\n" ); document.write( "\n" ); document.write( "3x^3y^2-3x^2y^2+3xy^2
\n" ); document.write( "

Algebra.Com's Answer #119643 by gonzo(654)\"\" \"About 
You can put this solution on YOUR website!
equation is \"3%2Ax%5E3%2Ay%5E2-3%2Ax%5E2%2Ay%5E2%2B3%2Ax%2Ay%5E2\"
\n" ); document.write( "looks like you can factor out 3*x*y^2 to get
\n" ); document.write( "\"3%2Ax%2Ay%5E2%2A%28x%5E2+-+x+%2B+1%29\"
\n" ); document.write( "quadratic formula to find the roots of \"x%5E2+-+x+%2B+1\" is
\n" ); document.write( "\"%28-b+%2B+sqrt%28b%5E2+-+4%2Aa%2Ac%29%29%2F%282%2Aa%29\" and \"%28-b+-+sqrt%28b%5E2+-+4%2Aa%2Ac%29%29%2F%282%2Aa%29\"
\n" ); document.write( "looking at \"x%5E2+-+x+%2B+1\" and using the quadratic formula, it looks like the solution to that quadratic equation is not real since
\n" ); document.write( "the part of the equation under the square root sign \"b%5E2+-+4%2Aa%2Ac\" is negative as shown below.
\n" ); document.write( "in the equation \"x%5E2+-+x+%2B+1\"
\n" ); document.write( "a = 1
\n" ); document.write( "b = -1
\n" ); document.write( "c = 1
\n" ); document.write( "4*a*c = 4
\n" ); document.write( "b^2 = 1
\n" ); document.write( "\"sqrt%28b%5E2+-+4%2Aa%2Ac%29\" equals \"sqrt%281-4%29\" = \"sqrt%28-3%29\" which is negative so you don't have a real solution.
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\n" ); document.write( "the answer appears to be
\n" ); document.write( "\"3%2Ax%2Ay%5E2%2A%28x%5E2+-+x+%2B+1%29\"
\n" ); document.write( "\"x%5E2+-+x+%2B+1\" appears to be prime because it can't be factored any further.
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