document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=162322>Question 162322</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Classify the conic section of each equation.\r<BR>\n" );
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document.write( "10. 25x^2 - 9y^2 = 144\r<BR>\n" );
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document.write( "I think this may be a circle? But im not for sure and I would love to see the correct steps to finding the answer, i know to rewrite x as x-0 and y as y-0, and i know that 144 is also 12^2,but im  not sure where to begin. Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119632 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119632\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Three things to check in conic sections: degree of x and y, coefficient and signs of coefficients.<BR>\n" );
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document.write( "Circle : Degree 2 for both x and y, equal coefficients, both positive.<BR>\n" );
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document.write( "Parabola : Degree 2 for y and degree 1 for y, coefficients not important.<BR>\n" );
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document.write( "Ellipse: Degree 2 for both x and y, unequal coefficients, both positive.<BR>\n" );
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document.write( "Hyperbola : Degree 2 for both x and y, coefficients not important, one positive, one negative.<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=25x%5E2+-+9y%5E2+=+144 ALIGN=MIDDLE  ALT=\"25x%5E2+-+9y%5E2+=+144\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x and y degree 2.<BR>\n" );
document.write( "Coefficients:One positive, one negative.<BR>\n" );
document.write( "Hyperbola.<BR>\n" );
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document.write( "You could also divide by 144 and look for general forms of conic sections.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=25x%5E2%2F144-9y%5E2%2F144=1 ALIGN=MIDDLE  ALT=\"25x%5E2%2F144-9y%5E2%2F144=1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The general form for a hyperbola is,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1 ALIGN=MIDDLE  ALT=\"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "In your case,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h=0 ALIGN=MIDDLE  ALT=\"h=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=k=0 ALIGN=MIDDLE  ALT=\"k=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2=%28144%2F25%29 ALIGN=MIDDLE  ALT=\"a%5E2=%28144%2F25%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=12%2F5 ALIGN=MIDDLE  ALT=\"a=12%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E2=%28144%2F9%29 ALIGN=MIDDLE  ALT=\"b%5E2=%28144%2F9%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b=12%2F3 ALIGN=MIDDLE  ALT=\"b=12%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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