document.write( "Question 162310: CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM:\r
\n" ); document.write( "\n" ); document.write( "Suppose the amount of a radioactive element remaining in a sample of 100 milligrams after x years can be described by A(x) = 100e^-0.01657x. How much is remaining after 257 years? Round to the nearest hundredth of a milligram.\r
\n" ); document.write( "\n" ); document.write( "a. 0.01 milli
\n" ); document.write( "b. 1.42 milli
\n" ); document.write( "c. 425.85 milli
\n" ); document.write( "d. 7070.31 milli
\n" ); document.write( "

Algebra.Com's Answer #119622 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Suppose the amount of a radioactive element remaining in a sample of 100
\n" ); document.write( " milligrams after x years can be described by A(x) = 100e^-0.01657x.
\n" ); document.write( " How much is remaining after 257 years?
\n" ); document.write( "Round to the nearest hundredth of a milligram.
\n" ); document.write( ":
\n" ); document.write( "A(x) = \"100%2Ae%5E%28-0.01657x%29\"
\n" ); document.write( ":
\n" ); document.write( "Substitute 257 for x;
\n" ); document.write( "A(x) = \"100%2Ae%5E%28-0.01657%2A257%29\"
\n" ); document.write( ":
\n" ); document.write( "A(x) = \"100%2Ae%5E-4.25849\"
\n" ); document.write( ":
\n" ); document.write( "on a good calc find: \"e%5E-4.25849\"
\n" ); document.write( "A(x) = 100 * .01414
\n" ); document.write( ":
\n" ); document.write( "A(x) = 1.41 milligrams
\n" ); document.write( "
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