document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161701>Question 161701</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation of the line containing (-1, 3) and perpendicular to the line containing (3, -5) and (-2, 7). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119614 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119614\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Find an equation of the line containing (-1, 3) and perpendicular to the line containing (3, -5) and (-2, 7).<BR>\n" );
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document.write( "This is a 2 step process.  1st find the slope m1, of the line.  Then find the line perpendicular.  Perpendicular means the slope is the negative inverse of the slope m1.<BR>\n" );
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document.write( "m1 = (y2-y1)/(x2-x1)<BR>\n" );
document.write( "m1 = (-5-7)/(3 -(-2))<BR>\n" );
document.write( "m1 = -12/5<BR>\n" );
document.write( "So the slope of the perpendicular is +5/12<BR>\n" );
document.write( "Use the slope-intercept eqn<BR>\n" );
document.write( "y-y3 = m*(x-x3) where (x3,y3) is the point (-1,3)<BR>\n" );
document.write( "y-3 - 5/12(x-(-1)<BR>\n" );
document.write( "y-3 = 5/12x + 5/12<BR>\n" );
document.write( "y = 5x/12 + 3 5/12  (slope-intercept form)<BR>\n" );
document.write( "or y = (5/12)x +41/12<BR>\n" );
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document.write( "12y = 5x + 41<BR>\n" );
document.write( "5x - 12y = -41  (standard form) </SPAN>\n" );
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