document.write( "Question 162149: Hector is performing a chemistry experiment that requires 140 millimeters of a 30% copper sulfate solution. He has a 25% copper sulfate solution and a 60% copper sulfate solution. How many milliliters of each solution should he mix to obtain the needed solution? \n" ); document.write( "
Algebra.Com's Answer #119601 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Hector is performing a chemistry experiment that requires 140 millimeters of \n" ); document.write( " a 30% copper sulfate solution. He has a 25% copper sulfate solution and a 60% \n" ); document.write( " copper sulfate solution. How many milliliters of each solution should he mix \n" ); document.write( " to obtain the needed solution? \n" ); document.write( ": \n" ); document.write( "Let x = amt of 60% solution \n" ); document.write( ": \n" ); document.write( "It states that total resulting solution should be 140 ml, therefore \n" ); document.write( "(140-x) = amt of 25% solution required \n" ); document.write( ": \n" ); document.write( "The equation: \n" ); document.write( ".60x + .25(140-x) = .30(140) \n" ); document.write( ".60x + 35 - .25x = 42 \n" ); document.write( ".60x - .25x = 42 - 35 \n" ); document.write( ".35x = 7 \n" ); document.write( "x = \n" ); document.write( "x = 20 ml of 60% solution \n" ); document.write( "and \n" ); document.write( "140 - 20 = 120 ml of 25% solution \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check: \n" ); document.write( ".6(20) + .25(120) = .3(140) \n" ); document.write( "12 + 30 = 42 \n" ); document.write( " |