document.write( "Question 162252: simplify the following expression by justifying each step:\r
\n" ); document.write( "\n" ); document.write( "cotA(secA-cosA) \n" ); document.write( "

Algebra.Com's Answer #119574 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( " $\"cot+%28alpha%29%28sec%28alpha%29-cos%28alpha%29%29\"$ , distribute
\n" ); document.write( " $\"cot%28alpha%29sec%28alpha%29-cot%28alpha%29cos%28alpha%29\"$
\n" ); document.write( "*Note: Reciprocal Identities: $\"sec%28alpha%29=1%2Fcos%28alpha%29\"$
\n" ); document.write( " $\"cot%28alpha%29%281%2Fcos%28alpha%29%29-cot%28alpha%29cos%28alpha%29\"$
\n" ); document.write( " $\"%28cot%28alpha%29-cot%28alpha%29cos%5E2%28alpha%29%29%2Fcos%28alpha%29\"$ , subtract by getting common denominator
\n" ); document.write( " $\"%28cot%28alpha%29%29%281-cos%5E2%28alpha%29%29%2Fcos%28alpha%29\"$
\n" ); document.write( "*Note: Pythagorean identities: $\"sin%5E2%28alpha%29%2Bcos%5E2%28alpha%29=1\"$
\n" ); document.write( " $\"%28cot%28alpha%29sin%5E2%28alpha%29%29%2Fcos%28alpha%29\"$
\n" ); document.write( "*Note: Quotient Identites: $\"cot%28alpha%29=cos%28alpha%29%2Fsin%28alpha%29\"$ --> $\"1%2Fsin%28alpha%29=cot%28alpha%29%2Fcos%28alpha%29\"$
\n" ); document.write( "So,
\n" ); document.write( " $\"%281%2Fsin%28alpha%29%29%28sin%5E2%28alpha%29%29\"$
\n" ); document.write( " $\"%281%2Fcross%28sin%28alpha%29%29%29%28cross%28sin%5E2%28alpha%29%29sin%28alpha%29%29\"$
\n" ); document.write( " $\"highlight%28sin%28alpha%29%29\"$ , ANSWER
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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