document.write( "Question 162222: Our teacher didn't explain much about using Cramer rule with fractions so im at a lost at this equation.
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document.write( "{(2/3)x + (1/5)y = 3
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document.write( "{(3/2)x + (5/3)y = (2/3)
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document.write( "If it makes it any easier, our teacher said we can also use subtitution and elimination method. \n" );
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Algebra.Com's Answer #119553 by stanbon(75887) ![]() You can put this solution on YOUR website! Our teacher didn't explain much about using Cramer rule with fractions so im at a lost at this equation.\r \n" ); document.write( "\n" ); document.write( "{(2/3)x + (1/5)y = 3 \n" ); document.write( "{(3/2)x + (5/3)y = (2/3)\r \n" ); document.write( "\n" ); document.write( "If it makes it any easier, our teacher said we can also use subtitution and elimination method. \n" ); document.write( "-------------------- \n" ); document.write( "The fact that you have fractions does not make any difference in \n" ); document.write( "using Cramer's Method.\r \n" ); document.write( "\n" ); document.write( "But you can get rid of the fractions: \n" ); document.write( "Multiply thru the 1st equation by 15 to get: \n" ); document.write( "10x + 3y = 45 \n" ); document.write( "Multiply thru the 2nd equation by 6 to get: \n" ); document.write( "9x + 10y = 4 \n" ); document.write( "------------------ \n" ); document.write( "Now, use Cramer or elimination to get: \n" ); document.write( "x = 6 \n" ); document.write( "y = -5 \n" ); document.write( "========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |