document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23245>Question 23245</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A coffee shop owner tried to make his own special blend of coffee b adding a percentage of colombian cofee to his basic grind. After experimenting he decide that a 30 0/0 blend was best. However, he was left with a supply of 20 0/0 and 50 0/0 columbian coffee blend. How many poubnds of the 20 0/0 blend would he have to add to the 50 0/0 blend to wind up with 100 lbs of the 30 0/0 blend? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11954 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11954\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Follow the columbian coffee in the blends.<BR>\n" );
document.write( "Let the amount of 20% blend be \"x\"<BR>\n" );
document.write( "Then the amount of 50% blend is \"100-x\"<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "   20%(x) + 50%(100-x) = 30%(100)<BR>\n" );
document.write( "    20x +5000-50x = 3000<BR>\n" );
document.write( "            -30x = -2000<BR>\n" );
document.write( "               x = 66 2/3 lbs. (amount of 20% blend)<BR>\n" );
document.write( "          100-x  = 33 1/3 lbs. ( amount of 50% blend)\r<BR>\n" );
document.write( "\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );