document.write( "Question 162165: how much pure acid should be mixed with 7 gallons of 50% acid solution in order to get an 80% acid solution? \n" ); document.write( "
Algebra.Com's Answer #119539 by KnightOwlTutor(293)![]() ![]() You can put this solution on YOUR website! Pure acid is 100% \n" ); document.write( "Convert % into decimal form 100/100 \n" ); document.write( "50%=50/100 \n" ); document.write( "80%=80/100\r \n" ); document.write( "\n" ); document.write( "X=# of gallons of pure acid\r \n" ); document.write( "\n" ); document.write( "1*x+7(.5)=(x+7)(.8)\r \n" ); document.write( "\n" ); document.write( "Use the distributive property\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+3.5=.8x+5.6\r \n" ); document.write( "\n" ); document.write( "Subtract .8x from both sides\r \n" ); document.write( "\n" ); document.write( ".2x+3.5=5.6\r \n" ); document.write( "\n" ); document.write( "Subtract 3.5 from both sides\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".2x=2.1\r \n" ); document.write( "\n" ); document.write( "Divide both sides by .2\r \n" ); document.write( "\n" ); document.write( "x=10.5 gallons of pure acid\r \n" ); document.write( "\n" ); document.write( "Let's double check our answer\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "10.5+3.5=(10.5+7)(.8)\r \n" ); document.write( "\n" ); document.write( "14=14 \n" ); document.write( " |