document.write( "Question 162180: The length of a rectangle is twice the width. The perimeter is 84cm more than the width. Make a diagram and find the rectangle's dimensions. \n" ); document.write( "
Algebra.Com's Answer #119535 by KnightOwlTutor(293)![]() ![]() You can put this solution on YOUR website! We know that the equation for determining the perimeter of a rectangle is P=L+w+L=W P=2L+2W\r \n" ); document.write( "\n" ); document.write( "We know that L=2W\r \n" ); document.write( "\n" ); document.write( "We know that the perimeter is=W+84cm\r \n" ); document.write( "\n" ); document.write( "W+84=2(2W)+2W \n" ); document.write( "w+84=4W+2W \n" ); document.write( "W+84=6W\r \n" ); document.write( "\n" ); document.write( "Subtract w from both sides\r \n" ); document.write( "\n" ); document.write( "84=5W\r \n" ); document.write( "\n" ); document.write( "Divide both sides by 5\r \n" ); document.write( "\n" ); document.write( "W=16.8\r \n" ); document.write( "\n" ); document.write( "L=33.6\r \n" ); document.write( "\n" ); document.write( "2(16.8)+2(33.6)=33.6+67.2=100.8\r \n" ); document.write( "\n" ); document.write( "Let's double check our answer\r \n" ); document.write( "\n" ); document.write( "We know that the perimeter was 84 more than the width\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "100.8-84=16.8\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |