document.write( "Question 160791This question is from textbook
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document.write( ": If a line passes through (3,-1) and is perpendicular to the graph of y=(-1/3)x-4,what would the slope-intercept form be? \n" );
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Algebra.Com's Answer #119524 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! If a line passes through (3,-1) and is perpendicular to the graph of y=(-1/3)x-4,what would the slope-intercept form be? \n" ); document.write( "-------------------- \n" ); document.write( "y=(-1/3)x-4 is the slope-intercept form, so the slope is -1/3 \n" ); document.write( "To be perpendicular, the slope of the other line is the negative inverse, or +3 \n" ); document.write( "---------------- \n" ); document.write( "Then use the slope-intercept and the point: \n" ); document.write( "y-y1 = m*(x-x1) (x1,y1) is (3,-1) \n" ); document.write( "y -(-1) = 3*(x-3) \n" ); document.write( "y+1 = 3x-9 \n" ); document.write( "y = 3x - 10 \n" ); document.write( " \n" ); document.write( " |