document.write( "Question 162122: jason has invested a total of $25,000 in two accounts and at the end of one year earned $2,600 in simple intrest. one account earns 7% simple intrest and the other earns 12% simple intrest. What is the amount invested in each account? \n" ); document.write( "
Algebra.Com's Answer #119488 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .12x+.07(25,000-x)=2,600 \n" ); document.write( ".12x+1,750-.07x=2,600 \n" ); document.write( ".05x=2,600-1,750 \n" ); document.write( ".05x=850 \n" ); document.write( "x=850/.05 \n" ); document.write( "x=17,000 invested @ 12%. \n" ); document.write( "25,000-17,000=8,000 invested @ 7%. \n" ); document.write( "proof: \n" ); document.write( ".12*17,000+.07*8,000=2,600 \n" ); document.write( "2,040+560=2,600 \n" ); document.write( "2,600=2,600 \n" ); document.write( " |