document.write( "Question 162146: Nathan made a triangular pennant for the band booster club. The are of the pennant is 80 square feet. The base of the pennant is 12 feet shorter than the height.\r
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document.write( "a) what are the lengths of the base and height of the pennant?
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document.write( "b)what are the dimensions of the pennant if the base is only 6 feet shorter that the height?\r
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document.write( "(I really do not understand this problem at all; do we use 1/2(b)(h)\r
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document.write( "please help soon! \n" );
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Algebra.Com's Answer #119472 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! AREA OF A TRIANGLE=BH/2 \n" ); document.write( "(H-12)H/2=80 \n" ); document.write( "(H^2-12H)/2=80 \n" ); document.write( "H^2-12H=2*80 \n" ); document.write( "H^2-12H=160 \n" ); document.write( "H^2-12H-160=0 \n" ); document.write( "(H-20)(H+8)=0 \n" ); document.write( "H-20=0 \n" ); document.write( "H=20 IS THE HEIGHT. \n" ); document.write( "20-12=8 FOR THE BASE. \n" ); document.write( "PROOF: \n" ); document.write( "8*20/2=80 \n" ); document.write( "160/2=80 \n" ); document.write( "80=80\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |