document.write( "Question 161968: A radiator contains 6 quarts of a 25% antifreeze solution. How much anitfreeze should be drained and replaced with pure antifreeze to yield a 33% solution? \n" ); document.write( "
Algebra.Com's Answer #119424 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A radiator contains 6 quarts of a 25% antifreeze solution. How much antifreeze
\n" ); document.write( " should be drained and replaced with pure antifreeze to yield a 33% solution?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt to be removed and amt to be added (1x = pure antifreeze)
\n" ); document.write( ":
\n" ); document.write( "a decimal equation of the amt of antifreeze
\n" ); document.write( ".25(6-x) + 1x = .33(6)
\n" ); document.write( ":
\n" ); document.write( "1.5 - .25x + 1x = 1.98
\n" ); document.write( ":
\n" ); document.write( "-.25x + 1x = 1.98 - 1.5
\n" ); document.write( ":
\n" ); document.write( ".75x = .48
\n" ); document.write( "x = \".48%2F.75\"
\n" ); document.write( "x = .64 qts to replaced
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution in the original equation
\n" ); document.write( ".25(6 - .64) + 1(.64) = .33(6)
\n" ); document.write( ".25(5.36) + .64 = 1.98
\n" ); document.write( "1.34 + .64 = 1.98; confirms our solution
\n" ); document.write( "
\n" );