document.write( "Question 162018: 7. What is the standard equation of the circle with radius 5, and center (-5,-1)? \r
\n" ); document.write( "\n" ); document.write( "A (x-5)^2 + (y-1)^2 = 25
\n" ); document.write( "B (x+5)^2 + (y+1)^2 = 25
\n" ); document.write( "C (x+5)^2 + (y+5)^2 = 5
\n" ); document.write( "D A circle cannot have a center at (-5,-1).
\n" ); document.write( "E (x-5)^2 - (y-1)^2 = 25
\n" ); document.write( "F (x+5)^2 - (y+1)^2 = 25\r
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\n" ); document.write( "\n" ); document.write( "I used the formula for a circle and plugged the information in, and I got F for the right answer. But choice D is confusing me and i wanted to make sure F really is correct. Thank you!
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Algebra.Com's Answer #119399 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Since the center is (-5,-1) this means that h=-5 and k=-1. Remember, the center is at (h,k). Also, since the radius is 5, this tells us that r=5\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\" Start with the general equation of any circle\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-%28-5%29%29%5E2%2B%28y-%28-1%29%29%5E2=5%5E2\" Plug in \"h=-5\", \"k=-1\", and \"r=5\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B5%29%5E2%2B%28y%2B1%29%5E2=5%5E2\" Rewrite \"x-%28-5%29\" as \"x%2B5\". Rewrite \"y-%28-1%29\" as \"y%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B5%29%5E2%2B%28y%2B1%29%5E2=25\" Square 5 to get 25\r
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\n" ); document.write( "\n" ); document.write( "So the standard equation of the circle with a radius of 5 and the center (-5,-1) is \"%28x%2B5%29%5E2%2B%28y%2B1%29%5E2=25\" which means that the answer is B
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