document.write( "Question 162002: pls.help me solve the following quadratic equation by factoring:\r
\n" ); document.write( "\n" ); document.write( "\"2x%5E2-3x%2B1=0\"
\n" ); document.write( "\"4x%5E2%2B9x=9\"
\n" ); document.write( "\"2y%5E2%2By=-11y\"
\n" ); document.write( "\"y%5E2-7-44=0\"
\n" ); document.write( "\"6x%5E2%2B11x-1=0\"\r
\n" ); document.write( "\n" ); document.write( "pls. submit your answer as soon as possible i need to pass it tomorrow
\n" ); document.write( "im begging you pls..
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Algebra.Com's Answer #119397 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
pls.help me solve the following quadratic equation by factoring:
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document.write( "\"2x%5E2-3x%2B1=0\"\r\n" );
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document.write( "Multiply the \"2\" in front by the \"matrix%281%2C1%2C%22%2B1%22%29\",\r\n" );
document.write( "getting \"2\".  So we write down\r\n" );
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document.write( "\"1%2A2\"\r\n" );
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document.write( "as the only way to find two factors of \"2\".\r\n" );
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document.write( "Next look at the sign of the last term \"matrix%281%2C1%2C%22%2B1%22%29\" \r\n" );
document.write( "on the left.  It is \"matrix%281%2C1%2C%22%2B%22%29\" so beside \"1%2A2\"\r\n" );
document.write( "we write the sum \"1%2B2\", and what it equals, \"3\":.  \r\n" );
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document.write( "\"1%2A2\"   \"1%2B2=3\"\r\n" );
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document.write( "We observe that the absolute\r\n" );
document.write( "value of the coefficient of the middle term on the left of\r\n" );
document.write( "\"2x%5E2-3x%2B1=0\" is \"3\" so we replace the \"3\" by\r\n" );
document.write( "\"%281%2B2%29\", so\r\n" );
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document.write( "\"2x%5E2-3x%2B1=0\"   becomes\r\n" );
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document.write( "\"2x%5E2-%281%2B2%29x%2B1=0\"\r\n" );
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document.write( "Now place the \"x\" on the left of the \"%281%2B2%29\" as\r\n" );
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document.write( "\"2x%5E2-x%281%2B2%29%2B1=0\"\r\n" );
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document.write( "Us the distributive property to multiply out \"-x%281%2B2%29\"\r\n" );
document.write( "as \"-x-2x\". So now we have:\r\n" );
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document.write( "\"2x%5E2-x-2x%2B1=0\"\r\n" );
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document.write( "Out of the first two terms on the left ONLY, \"2x%5E2-x\",\r\n" );
document.write( "we can factor out \"x\", getting \"x%282x-1%29\" \r\n" );
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document.write( "Out of the last two terms on the left ONLY, \"-2x%2B1\",\r\n" );
document.write( "we can factor out \"-1\", getting \"-1%282x-1%29\".\r\n" );
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document.write( "[Notice when the first of the last two terms begins\r\n" );
document.write( "with a \"-\" sign, always take out a \"-\" term, which\r\n" );
document.write( "will invariably change the sign of the second term.]\r\n" );
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document.write( "So we have\r\n" );
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document.write( "\"x%282x-1%29-1%282x-1%29=0\"\r\n" );
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document.write( "Now we take out the parentheses \"%282x-1%29\" as a\r\n" );
document.write( "common factor and leave the \"x\" and the \"-1\"\r\n" );
document.write( "to put inside parentheses, like this:\r\n" );
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document.write( "\"%282x-1%29%28x-1%29=0\"\r\n" );
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document.write( "Noqw we use the zero-factor principle where we \r\n" );
document.write( "set each factor = 0:\r\n" );
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document.write( "  \r\n" );
document.write( "So the solution set is \"matrix%281%2C5%2C+%22%7B%22%2C+1%2F2%2C+%22%2C%22%2C+1%2C+%22%7D%22%29\"\r\n" );
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document.write( "That's just the first one.  If I have time I will come back\r\n" );
document.write( "and finish the rest.  So check this site later, for I will\r\n" );
document.write( "probably do some more.\r\n" );
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document.write( "Edwin

\n" ); document.write( "\"4x%5E2%2B9x=9\"
\n" ); document.write( "\"2y%5E2%2By=-11y\"
\n" ); document.write( "\"y%5E2-7-44=0\"
\n" ); document.write( "\"6x%5E2%2B11x-1=0\"
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