document.write( "Question 162005: pls.help me solve the following quadratic equation by factoring:\r
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document.write( "pls. submit your answer as soon as possible i need to pass it tomorrow
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document.write( "im begging you pls.. \n" );
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Algebra.Com's Answer #119394 by KnightOwlTutor(293)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "\n" ); document.write( "We know that the last term must be 1\r \n" ); document.write( "\n" ); document.write( "Set up the equation like this \n" ); document.write( "it could be -1,-1 or 1,1\r \n" ); document.write( "\n" ); document.write( "Because you have a negative middle term it is most likely -1,-1\r \n" ); document.write( "\n" ); document.write( "(2x-1)(x-1)=0\r \n" ); document.write( "\n" ); document.write( "Therefore the solution is x= 1/2 or 1 we need to make the equation=0 and the only way to accomplish this is to make one or both terms =0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We need to subtract 9 from both sides of the equation \r \n" ); document.write( "\n" ); document.write( "4x^2+9x-9=0\r \n" ); document.write( "\n" ); document.write( "We need to find two numbers that have a product of 9 the possibilities are 3,3 \n" ); document.write( "9,1 \n" ); document.write( "We have a negative number so we know that the product is -\r \n" ); document.write( "\n" ); document.write( "We then need to know what 2 numbers give a product of 4\r \n" ); document.write( "\n" ); document.write( "2,2 or 4,1\r \n" ); document.write( "\n" ); document.write( "Let's set up the equation\r \n" ); document.write( "\n" ); document.write( "using 3,3\r \n" ); document.write( "\n" ); document.write( "(_x-3)(_x+3) \n" ); document.write( "The middle terms need to add up to 9x Let's try 4 and 1\r \n" ); document.write( "\n" ); document.write( "(4x-3)(x+3) The middle term for this problem is -3x+12x=9x\r \n" ); document.write( "\n" ); document.write( "We have the correct factors \n" ); document.write( "the solution is x=3/4 or -3\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here we add 11y to both sides of the equation\r \n" ); document.write( "\n" ); document.write( "2y^2+y+11y=0\r \n" ); document.write( "\n" ); document.write( "2y^2+12y=0\r \n" ); document.write( "\n" ); document.write( "factor out 2 \n" ); document.write( "2(y^2+6)=0 \n" ); document.write( "y=sqrt6 i \n" ); document.write( "remember that i=sqrt of -1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First we try to calculate the numbers that generate a product of 44\r \n" ); document.write( "\n" ); document.write( "4,11 or 44,1\r \n" ); document.write( "\n" ); document.write( "Let's try 4,11\r \n" ); document.write( "\n" ); document.write( "(y-11)(y+4)\r \n" ); document.write( "\n" ); document.write( "y =11 or -4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6x^2+11x-1=0 \n" ); document.write( "ax^2+bx+c=0 a=6 b=11 c=-1
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