document.write( "Question 161897: FACTOR BY GROUPING
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Algebra.Com's Answer #119392 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "FACTOR BY GROUPING\r\n" );
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document.write( "\"3AX%2B3AY%2B4X%2B4Y\"\r\n" );
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document.write( "In the first two terms only, \"3AX%2B3AY\", we can factor out\r\n" );
document.write( "\"3A\" and get \"3A%2A%28X%2BY%29\".\r\n" );
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document.write( "In the last two terms only, \"matrix%281%2C2%2C+%22%2B%22%2C+4X%2B4Y+%29\", we can factor out\r\n" );
document.write( "\"matrix%281%2C1%2C%22%2B4%22%29\" and get \"matrix%281%2C1%2C%22%2B4%2A%28X%2BY%29%22%29\".  So we have this:\r\n" );
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document.write( "\"3A%2A%28X%2BY%29%2B4%28X%2BY%29\"\r\n" );
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document.write( "Now we can take out the parentheses as the common factor\r\n" );
document.write( "\"%28X%2BY%29\" leaving the \"3A\" and the \"matrix%281%2C1%2C%22%2B4%22%29\",\r\n" );
document.write( "so the final factored form is:\r\n" );
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document.write( "\"%28X%2BY%29%283A%2B4%29\" \r\n" );
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document.write( "FACTOR BY FINDING THE GREATEST COMMON FACTOR: \r\n" );
document.write( "\"25y%5E5-15y%5E4%2B+6y%5E3%2B5y%5E2\"\r\n" );
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document.write( "We can factor \"y%5E2\" out of all the terms:\r\n" );
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document.write( "\"y%5E2%2825y%5E3-15y%5E2%2B+6y%2B5%29\"\r\n" );
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document.write( "That's as far as we can go, because there is no way\r\n" );
document.write( "to factor what is inside the parentheses by grouping:\r\n" );
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document.write( "Edwin
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