document.write( "Question 161991: Please help, thank you.
\n" ); document.write( "At 1:00 p.m., a car leaves a city and travels north at a rate of 55 mi/h. An hour later, a second car leaves the city and travels south at a rate of 60 mi/hr. At what time will the two cars be 285 miles apart?
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Algebra.Com's Answer #119375 by nerdybill(7384)\"\" \"About 
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Let t = amount of time northbound car traveled
\n" ); document.write( "then because the southbout left an hour later
\n" ); document.write( "t-1 = amount of time the southbound car traveled
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\n" ); document.write( "Using the distance formula: d = rt
\n" ); document.write( "where
\n" ); document.write( "d is distance
\n" ); document.write( "r is rate or speed
\n" ); document.write( "t is time
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\n" ); document.write( "\"distance traveled by northbound\" + \"distance traveled by southbound\" = \"distance apart\"
\n" ); document.write( "55t + 60(t-1) = 285
\n" ); document.write( "55t + 60t - 60 = 285
\n" ); document.write( "115t = 345
\n" ); document.write( "t = 3 hours (time traveled by northbound car)
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\n" ); document.write( "Since he started at 1:00 p.m
\n" ); document.write( "Adding 3 hours to that will mean that at
\n" ); document.write( "4:00 p.m. (the cars are 285 miles apart)
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