document.write( "Question 161932: find the measure of an angle such that the difference between its supplement and three times its compliment is 16 degrees. \n" ); document.write( "

Algebra.Com's Answer #119373 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( " $\"A%2BB=90%5Eo\"$ , complementary angles
\n" ); document.write( " $\"A%2BB=180%5Eo\"$ , supplementary angles
\n" ); document.write( "Via condition:
\n" ); document.write( " $\"%28180-B%29-3%2890-B%29=16%5Eo\"$ ----------------> working eqn
\n" ); document.write( " $\"180-B-270%2B3B=16%5Eo\"$
\n" ); document.write( " $\"2B=16%2B270-180=106%5Eo\"$
\n" ); document.write( " $\"cross%282%29B%2Fcross%282%29=cross%28106%2953%2Fcross%282%29\"$
\n" ); document.write( " $\"B=53%5Eo\"$ ANSWER
\n" ); document.write( ".
\n" ); document.write( "Complement Angle: $\"A=90-B=90-53=37%5Eo\"$
\n" ); document.write( "Supplement Angle: $\"A=180-53=127%5Eo\"$
\n" ); document.write( "Check via working eqn:
\n" ); document.write( " $\"180-53-3%2890-53%29=16%5Eo\"$
\n" ); document.write( " $\"127-3%2837%29=16%5Eo\"$
\n" ); document.write( " $\"127%5Eo-111%5Eo=16%5Eo\"$
\n" ); document.write( " $\"16%5Eo=16%5Eo\"$
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

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