document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161990>Question 161990</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0078603927/algebrahomeworkh>Algebra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Please can you help me with Arithmetic Sequences because I don't know how to <BR>\n" );
document.write( "do it. The problem say find the next three terms of each arithmetic sequence. <BR>\n" );
document.write( "The problem is 7/12,1_1/3,2_1/12,2_5/6,....<BR>\n" );
document.write( "Thanks for your help because I don't get how to do it so if you help me out to <BR>\n" );
document.write( "were I can do it on my own then thanks a lot.It's on page 236 my teacher wants <BR>\n" );
document.write( "me to do all the even numbers on the practice and apply. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119372 by </B><A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><B>KnightOwlTutor(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KnightOwlTutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I would first convert all terms into fractions\r<BR>\n" );
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document.write( "7/12,4/3,25/12,17/6\r<BR>\n" );
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document.write( "The difference between 7/12 and 4/3\r<BR>\n" );
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document.write( "We first need to find the common denominator:12\r<BR>\n" );
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document.write( "7/12 <BR>\n" );
document.write( "(4/3)(4/4)=16/12   16/12-7/12=9/12\r<BR>\n" );
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document.write( "The difference between 4/3 and 25/12  the common denominator is also 12\r<BR>\n" );
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document.write( "25/12-16/12=9/12\r<BR>\n" );
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document.write( "The difference between 25/12 and 17/6 The common denomiator is 12\r<BR>\n" );
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document.write( "34/12 -25/12=9/12\r<BR>\n" );
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document.write( "So 9/12 is added to a previous term \r<BR>\n" );
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document.write( "34/12+9/12=43/12=3_7/12\r<BR>\n" );
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document.write( "43/12+9/12=52/12=13/3 or 4_1/3\r<BR>\n" );
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document.write( "52/12+9/12=61/12=5_1/12\r<BR>\n" );
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document.write( "3_7/12,4_1/3,5_1/12\r<BR>\n" );
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document.write( " </SPAN>\n" );
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