document.write( "Question 161982: Please help.
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document.write( "How many pounds of hamburger that costs $1.60 per pound must be mixed with 70 pounds of hamburger that costs $2.10 per pound to make a mixture that costs $1.70 per pound. \n" );
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Algebra.Com's Answer #119368 by KnightOwlTutor(293)![]() ![]() You can put this solution on YOUR website! X=lbs of hamburger that costs$1.60 \n" ); document.write( "70=lbs of hamburger that costs $2.10\r \n" ); document.write( "\n" ); document.write( "Even thought the cost varies the total quantity of meat is constant.\r \n" ); document.write( "\n" ); document.write( "1.60x+(2.10)(70)=1.70(x+70)\r \n" ); document.write( "\n" ); document.write( "1.60x+147=1.70x+119\r \n" ); document.write( "\n" ); document.write( "Subtract 1.60x from both sides \r \n" ); document.write( "\n" ); document.write( "subtract 119 from both sides \n" ); document.write( "28=.1x\r \n" ); document.write( "\n" ); document.write( "divide both sides by .1\r \n" ); document.write( "\n" ); document.write( "280=x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's doublecheck our answer by replacing the x with 280\r \n" ); document.write( "\n" ); document.write( "1.6(280)+147=(350)1.7\r \n" ); document.write( "\n" ); document.write( "448+147=595\r \n" ); document.write( "\n" ); document.write( "595=595 \n" ); document.write( " \n" ); document.write( " |