document.write( "Question 161974: 1. A man is 4 times as old as his son now. Six years ago, he was 7 times as ols as his son during that time . Find their present ages? \n" ); document.write( "
Algebra.Com's Answer #119366 by KnightOwlTutor(293)\"\" \"About 
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x=boy's current age\r
\n" ); document.write( "\n" ); document.write( "4x=father's current age\r
\n" ); document.write( "\n" ); document.write( "The algebraic equation is as follows.We need to have the ages equal on both sides so we generate an equation that reflects their ages 6 years ago.\r
\n" ); document.write( "\n" ); document.write( "Using current age ratios to calculate their ages 6 years ago.\r
\n" ); document.write( "\n" ); document.write( "(4x-6)=father's age 6 years ago\r
\n" ); document.write( "\n" ); document.write( "x-6=age of son 6 years ago\r
\n" ); document.write( "\n" ); document.write( "4x-6+x-6=7(x-6)+(x-6)\r
\n" ); document.write( "\n" ); document.write( "Use the distributive property and simplify by combining like terms\r
\n" ); document.write( "\n" ); document.write( "5x-12=7x-42+x-6\r
\n" ); document.write( "\n" ); document.write( "5x-12=8x-48\r
\n" ); document.write( "\n" ); document.write( "Add 12 to both sides\r
\n" ); document.write( "\n" ); document.write( "Subtract 8x from both sides\r
\n" ); document.write( "\n" ); document.write( "-3x=-36\r
\n" ); document.write( "\n" ); document.write( "divide both sides by (-3)\r
\n" ); document.write( "\n" ); document.write( "x=12 is the son's current age
\n" ); document.write( "4x=48 is the father's current age\r
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\n" ); document.write( "\n" ); document.write( "Let's double check our answer by calulation their ages 6 years ago\r
\n" ); document.write( "\n" ); document.write( "12-6=6\r
\n" ); document.write( "\n" ); document.write( "48-8=42\r
\n" ); document.write( "\n" ); document.write( "Six years ago the father was 7x older than his son\r
\n" ); document.write( "\n" ); document.write( "6y=42\r
\n" ); document.write( "\n" ); document.write( "y=7. The answer is correct.\r
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