document.write( "Question 161974: 1. A man is 4 times as old as his son now. Six years ago, he was 7 times as ols as his son during that time . Find their present ages? \n" ); document.write( "
Algebra.Com's Answer #119360 by vleith(2983)\"\" \"About 
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Let M be the age of the man and S be the age of his son.
\n" ); document.write( "Given \"M+=+4S\" and \"M-6+=+7%28S-6%29\"
\n" ); document.write( "\"M-6+=+7%28S-6%29\"
\n" ); document.write( "\"M-6+=+7S+-+42\"
\n" ); document.write( "\"M+=+7S+-+36\" \r
\n" ); document.write( "\n" ); document.write( "Now, substitute for M using the first equation \"M+=+4S\"
\n" ); document.write( "So
\n" ); document.write( "\"M+=+7S+-+36\"
\n" ); document.write( "\"4S+=+7S+-+36+\"
\n" ); document.write( "\"-3S+=+-36\"
\n" ); document.write( "\"S+=+12\"\r
\n" ); document.write( "\n" ); document.write( "So the son is 12 and the dad is \"4S\" = \"4%2A12\" = \"48\"\r
\n" ); document.write( "\n" ); document.write( "Make sure to check your answers
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