document.write( "Question 161957: Classify the conic section
\n" ); document.write( " x^2 + y^2 = 121 \r
\n" ); document.write( "\n" ); document.write( "A hyperbola
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\n" ); document.write( "D circle
\n" ); document.write( "E parabola
\n" ); document.write( "F line\r
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\n" ); document.write( "\n" ); document.write( "I believe the answer is B. But I am not 100% sure, and Id love to know if that is correct, and if not, what is? Thank you so much for your time.
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Algebra.Com's Answer #119344 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "The equation \"x%5E2+%2B+y%5E2+=+121\" could be rewritten as \"%28x-0%29%5E2+%2B+%28y-0%29%5E2+=+121\" (since adding/subtracting 0 doesn't affect the equation). \r
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\n" ); document.write( "\n" ); document.write( "Also, take note that \"11%5E2=121\". So this also means that \"%28x-0%29%5E2+%2B+%28y-0%29%5E2+=+121\" further becomes \"%28x-0%29%5E2+%2B+%28y-0%29%5E2+=+11%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Remember, the formula for any circle is \"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\" where the center is at (h,k) and the radius is \"r\". Since the equation above fits this format, this shows us that the equation \"x%5E2+%2B+y%5E2+=+121\" is a circle\r
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\n" ); document.write( "\n" ); document.write( "Note: if you aren't entirely sure, solve for \"y\" and graph to get a visual clue (however, this won't fully confirm it every time)
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