document.write( "Question 161949: 50(3A-B) - 20(B-2A) \n" ); document.write( "
Algebra.Com's Answer #119339 by jim_thompson5910(35256)\"\" \"About 
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document.write( "50(3A-B) - 20(B-2A) = 50(3A)-50(B) - 20(B)-(-20)(2A)\r\n" );
document.write( "                    = 150A - 50B - 20B + 40A\r\n" );
document.write( "                    = 190A - 70B\r\n" );
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