document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161947>Question 161947</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A photo is 3 inches longer than it is wide. A 2-inch border is placed around the photo making the total area of the photo and border 108 square inches. What are the dimensions of the photo? \r<BR>\n" );
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document.write( "I know the length and the width are are 12 and 9. I assume that I would subtract 2 from both of these in for the answer. I just don't know how to write it in the form of an equation.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119338 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119338\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> actually, subtract 4 (2 at each end)\r<BR>\n" );
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document.write( "dimensions of photo __ x and x+3\r<BR>\n" );
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document.write( "with border __ x+4 and x+7\r<BR>\n" );
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document.write( "(x+4)(x+7)=108 __ x^2+11x-80=0 __ factoring __ (x+16)(x-5)=0\r<BR>\n" );
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document.write( "x+16=0 __ x=-16 __ negative value not realistic\r<BR>\n" );
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document.write( "x-5=0 __ x=5  __  substituting __ x+3=8 </SPAN>\n" );
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