document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161910>Question 161910</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0130584150/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> 2. Consider the equation a/4 = 20 - a/6\r<BR>\n" );
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document.write( "   a. Multiply each side by 12 and solve the resulting equation.<BR>\n" );
document.write( "   B. Multiply each side by 24 and solve the resulting equation.<BR>\n" );
document.write( "   c. What conclusions can you make from your work in parts a and b?\r<BR>\n" );
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document.write( "If you can show me the process of writing all the steps to solving this kind of equation that would be great. I have a way in my book i just can't understand it. Cause i dont learn by reading i learn from doing.\r<BR>\n" );
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document.write( "Thanks  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119313 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119313\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a/4 = 20 - a/6<BR>\n" );
document.write( "12(A/4)=12*20+12(-A/6)<BR>\n" );
document.write( "12A/4=240-12A/6<BR>\n" );
document.write( "3A=240-2A<BR>\n" );
document.write( "3A+2A=240<BR>\n" );
document.write( "5A=240<BR>\n" );
document.write( "A=240/5<BR>\n" );
document.write( "A=48 ANSWER.<BR>\n" );
document.write( "24(A/4)=24*20+24(-A/6)<BR>\n" );
document.write( "24A/4=480-24A/6<BR>\n" );
document.write( "6A=480-4A<BR>\n" );
document.write( "6A+4A=480<BR>\n" );
document.write( "10A=480<BR>\n" );
document.write( "A=480/10<BR>\n" );
document.write( "A=48 ANSWER.<BR>\n" );
document.write( "CONCLUSION: ANY COMMON MULTIPLIER, NOT NECESSARY THE LOWEST, CAN BE USED TO SOLVE THESE FRACTIONAL EQUATIONS <BR>\n" );
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document.write( "ANOTHER METHOD VERY SIMILAR BUT WITH LESS STEPS IS:A/4+A/6=20<BR>\n" );
document.write( "(3A+2A)/12=20<BR>\n" );
document.write( "5A/12=20<BR>\n" );
document.write( "5A=12*20<BR>\n" );
document.write( "5A=240<BR>\n" );
document.write( "A=240/5<BR>\n" );
document.write( "A=48 ANSWER.<BR>\n" );
document.write( "A/4+A/6=20<BR>\n" );
document.write( "(6A+4A)/24=20<BR>\n" );
document.write( "10A=24*20<BR>\n" );
document.write( "10A=480<BR>\n" );
document.write( "A=480/10<BR>\n" );
document.write( "A=48 ANSWER. </SPAN>\n" );
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