document.write( "Question 161893: Hi- I am stumped on a homework problem.\r
\n" ); document.write( "\n" ); document.write( "Write an equation in standard form for the line that satisfied each set of conditions.
\n" ); document.write( " -passes thru the points (-1, 2)
\n" ); document.write( " -is parallel to the graph x-3y=14\r
\n" ); document.write( "\n" ); document.write( "I started with trying to find points for x and y, and then tried to apply that to slope-intercept form. After that, I got really confused. I would appreciate your guidance. Thank you! \n" ); document.write( "
Algebra.Com's Answer #119298 by Alan3354(69443)\"\" \"About 
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Hi- I am stumped on a homework problem.
\n" ); document.write( "Write an equation in standard form for the line that satisfied each set of conditions.
\n" ); document.write( "-passes thru the points (-1, 2)
\n" ); document.write( "-is parallel to the graph x-3y=14
\n" ); document.write( "----------------
\n" ); document.write( "Parallel means it has the same slope.
\n" ); document.write( "1st, find the slope of x-3y=14
\n" ); document.write( "Put into slope-intercept form y=mx+b
\n" ); document.write( "x-3y=14
\n" ); document.write( "-3y = -x + 14
\n" ); document.write( "y = (1/3)x - 14/3
\n" ); document.write( "The slope, m, = 1/3
\n" ); document.write( "Then use the slope intercept-form to find the equation
\n" ); document.write( "y-y1 = m*(x-x1) (x1,y1) is the point (-1,2)
\n" ); document.write( "y-2 = (1/3)*(x-(-1))
\n" ); document.write( "y-2 = (x+1)/3
\n" ); document.write( "3y-6 = x+1
\n" ); document.write( "x-3y = -7
\n" ); document.write( "Notice that it's x-3y in both eqns, only the intercept is different. It's parallel, just shifted.
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